Advertisements
Advertisements
प्रश्न
In the given figure, ΔABC ~ ΔADE. If AE : EC = 4 : 7 and DE = 6.6 cm, find BC. If 'x' be the length of the perpendicular from A to DE, find the length of perpendicular from A to BC in terms of 'x'.
उत्तर
ΔABC ∼ ΔADE
AE : EC = 4 : 7, DE = 6.6 cm, BC = ?
Draw AL ⊥ DE and AM ⊥ BC
And AL = x cm
Find AM in terms of x
∵ ΔADE ∼ ΔABC
∴ `(AE)/(AC) = (DE)/(BC)`
∴ `(AE)/(AC) = (AE)/(AE + EC) = 4/(4 + 7) = 4/11`
∴ `(DE)/(BC) = (AE)/(AC) \implies 4/11 = 6.6/(BC)`
`\implies BC = (6.6 xx 11)/4`
= `36.3/2`
= 18.15 cm
∵ AL ⊥ DE and on producing it to BC then AM ⊥ BC
`(AL)/(AM) = (AE)/(AC) \implies x/(AM) = 4/11`
`\implies AM = (11 xx x)/4 = 11/4 x`
APPEARS IN
संबंधित प्रश्न
E and F are points on the sides PQ and PR, respectively, of a ΔPQR. For the following case, state whether EF || QR:
PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm
In the given figure, AB and DE are perpendicular to BC.
1) Prove that ΔABC ∼ ΔDEC
2) If AB = 6 cm; DE = 4 cm and AC = 15 cm. Calculate CD.
3) Find the ratio of area of ΔABC: area of ΔDEC
State, true or false:
Two congruent polygons are necessarily similar.
In the given figure, ∠CAB = 90° and AD⊥BC. Show that ΔBDA ~ ΔBAC. If AC = 75cm, AB = 1m and BC = 1.25m, find AD.
In MBC, DE is drawn parallel to BC. If AD: DB=2:3, DE =6cm and AE =3.6cm, find BC and AC.
A model of a ship is made to a scale 1 : 300.
- The length of the model of the ship is 2 m. Calculate the length of the ship.
- The area of the deck of the ship is 180,000 m2. Calculate the area of the deck of the model.
- The volume of the model is 6.5 m3. Calculate the volume of the ship.
In the following figure, point D divides AB in the ratio 3 : 5. Find : `(AE)/(AC)`
Construct a triangle similar to a given triangle PQR with its sides equal to `2/3` of the corresponding sides of the triangle PQR (scale factor `2/3 < 1`)
From the given figure, prove that ΔABC ~ ΔEDF
In ΔDEF and ΔXYZ, `"DE"/"XY" = "FE"/"YZ"` and ∠E ≅ ∠Y. _______ test gives similarity between ΔDEF and ΔXYZ.