Advertisements
Advertisements
प्रश्न
In the given figure, point S is any point on side QR of ΔPQR Prove that: PQ + QR + RP > 2PS
उत्तर
In △PQS
PQ + QS > PS ...(1) (Sum of two sides of a traingle is greater than the third side)
In △PRS
RP + RS > PS ...(2) (Sum of two sides of a traingle is greater than the third side)
Adding (1) and (2), we get
PQ + QS + RP + RS > PS + PS
∴ PQ + (QS + SR) + PR > 2PS
∴ PQ + QR + RP > 2PS ...(Q - S - R)
APPEARS IN
संबंधित प्रश्न
The length of hypotenuse of a right angled triangle is 15. Find the length of median of its hypotenuse.
In ΔPQR, ∠Q = 90°, PQ = 12, QR = 5 and QS is a median. Find l(QS).
In the given figure, if seg PR ≅ seg PQ, show that seg PS > seg PQ.
Draw an obtuse angled Δ LMN. Draw its altitudes and denote the orthocentre by ‘O’.
The medians of a triangle cross each other at _______
The centroid of a triangle divides each medians in the ratio _______
In any triangle the centroid and the incentre are located inside the triangle
In the given figure, A is the midpoint of YZ and G is the centroid of the triangle XYZ. If the length of GA is 3 cm, find XA
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is ______.
If we join a vertex to a point on opposite side which divides that side in the ratio 1:1, then what is the special name of that line segment?
