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In ΔPQR, ∠Q = 90°, PQ = 12, QR = 5 and QS is a median. Find l(QS). - Geometry

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प्रश्न

In ΔPQR, ∠Q = 90°, PQ = 12, QR = 5 and QS is a median. Find l(QS).

योग

उत्तर

In △PQR, ∠Q = 90°      ...[Given]

△PQR is a right angle triangle.

∴ By Pythagoras theorem,

∴ PR2 = PQ2 + QR2          

⇒ PR= 122 + 52

⇒ PR= 144 + 25

⇒ PR= 169

⇒ PR = `sqrt169`

⇒ PR = 13   

In △PQR,

seg QS is the median on hypotenuse PR. 

∴ QS = `1/2`PR           ...[In a right angled triangle, the length of the median on the hypotenuse is half the length of the hypotenuse.]

∴ QS = `1/2 × 13`

∴ QS = 6.5 units 

Hence, the length of QS is 6.5 units.

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अध्याय 3: Triangles - Practice Set 3.3 [पृष्ठ ३८]

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बालभारती Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board
अध्याय 3 Triangles
Practice Set 3.3 | Q 3. | पृष्ठ ३८
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