Advertisements
Advertisements
प्रश्न
In the given figure, ratio of the area of triangle ABC to the area of triangle ACD is the same as the ratio of base BC of triangle ABC to the base CD of ΔACD.
विकल्प
True
False
उत्तर
This statement is True.
Explanation:
∵ Area of ΔABC : Area of ΔACD = `1/2` × BC × AC : `1/2` × CD × AC ......[∵ Area of triangle = Base × Height]
= BC : CD
APPEARS IN
संबंधित प्रश्न
Find the values of k for which the points A(k + 1, 2k), B(3k, 2k + 3) and (5k – 1, 5k) are collinear.
Find the area of the triangle whose vertices are: (2, 3), (-1, 0), (2, -4)
Find the area of the following triangle:
Prove that the points (a, b), (a1, b1) and (a −a1, b −b1) are collinear if ab1 = a1b.
Show that the points (-3, -3),(3,3) and C (-3 `sqrt(3) , 3 sqrt(3))` are the vertices of an equilateral triangle.
Find the third vertex of a ΔABC if two of its vertices are B(-3,1) and C (0,-2) and its centroid is at the origin
A(7, -3), B(5,3) and C(3,-1) are the vertices of a ΔABC and AD is its median. Prove that the median AD divides ΔABC into two triangles of equal areas.
Using integration, find the area of the triangle whose vertices are (2, 3), (3, 5) and (4, 4).
Find the area of the triangle whose vertices are (-2, 6), (3, -6), and (1, 5).
The area of a triangle with vertices A(3, 0), B(7, 0) and C(8, 4) is ______.