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प्रश्न
Show that : loga m ÷ logab m + 1 + log ab
उत्तर
loga m ÷ logab m = =` ( log_a m )/( log_(ab) m )`
=` ( log_m ab )/( log_(m) a ) [ Qlog_b a = 1/ (log_ab ) ]`
= loga ab `[ Q ( log_xx a) / (log_xx b ) = log_b a ]`
= loga a + loga b
= 1 + loga b
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