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प्रश्न
Solve for x: `("log"125)/("log"5)` = logx
उत्तर
`("log"125)/("log"5)` = logx
⇒ `("log"5^3)/("log"5)` = logx
⇒ `(3"log"5)/("log"5)` = logx
⇒ 3 = logx
⇒ 3log10 = log x ...(since log 10 = 1)
⇒ log 103 = logx
∴ x = 103
= 1000.
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