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प्रश्न
Solve for x: `("log"121)/("log"11)` = logx
उत्तर
`("log"121)/("log"11)` = logx
⇒ `("log"11^2)/("lo"11)` = logx
⇒ `(2"log"11)/("log"11)` = logx
= 2 = logx
⇒ 2log 10 = logx ...(since log 10 = 1)
⇒ log 102 = logx
∴ x = 102
= 100.
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