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प्रश्न
Given log10x = 2a and log10y = `b/2`. Write 102b + 1 in terms of y.
योग
उत्तर
log10y = `b/2`
⇒ y = 10b/2
⇒ y4 = 102b
⇒ 10y4 = 102b x 10
⇒ 102b + 1 = 10y4
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