Given Log10x = 2a and Log10y = B/2. Write 10a In Terms of X. - Mathematics

Given log₁₀x = 2a and log₁₀y = `b/2`. Write 10^a in terms of x.

योग

log₁₀x = 2a
⇒ x = 10^2a ...[ Removing logarithm from both sides ]
⇒ x^1/2 = 10^a
⇒ 10^a = x^1/2

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