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प्रश्न
Given log10x = 2a and log10y = `b/2`. Write 10a in terms of x.
उत्तर
log10x = 2a
⇒ x = 102a ...[ Removing logarithm from both sides ]
⇒ x1/2 = 10a
⇒ 10a = x1/2
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