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प्रश्न
Prove that `("log"_"p" x)/("log"_"pq" x)` = 1 + logp q
उत्तर
L.H.S.
= `("log"_"p" x)/("log"_"pq" x)`
= `((("log" x)/("log""p")))/((("log"x)/("log""pq"))`
= `("log"x)/("log""p") xx ("log""pq")/("log"x)`
= `("log""pq")/("log""p")`
= `("log""p" + "log""q")/("log""p")`
= `1 + ("log""q")/("log""p")`
= 1 + logp q
= R.H.S.
Hence proved.
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