Advertisements
Advertisements
प्रश्न
Express the following in a form free from logarithm:
3 log x - 2 log y = 2
उत्तर
3 log x - 2 log y = 2
⇒ log x3 - log y2
= 2 log 10
⇒ `"log"(x^3/y^2)` = log 102
= log 100
⇒ `(x^3/y^2)` = 100
⇒ x3 = 100 y2.
APPEARS IN
संबंधित प्रश्न
If log`( a - b )/2 = 1/2( log a + log b )`, Show that : a2 + b2 = 6ab.
If log√27x = 2 `(2)/(3)` , find x.
If p = log 20 and q = log 25 , find the value of x , if 2log( x + 1 ) = 2p - q.
If log2(x + y) = log3(x - y) = `log 25/log 0.2`, find the values of x and y.
If a2 = log x , b3 = log y and `a^2/2 - b^3/3` = log c , find c in terms of x and y.
Solve the following:
log ( x + 1) + log ( x - 1) = log 11 + 2 log 3
Solve for x: `("log"128)/("log"32)` = x
If log 3 m = x and log 3 n = y, write down
32x-3 in terms of m
If 2 log x + 1 = log 360, find: log (3 x2 - 8)
Prove that: `(1)/("log"_2 30) + (1)/("log"_3 30) + (1)/("log"_5 30)` = 1
