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Given X = Log1012 , Y = Log4 2 X Log109 and Z = Log100.4 , Find : (I) X - Y - Z (Ii) 13x - Y - Z - Mathematics

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प्रश्न

Given x = log1012 , y = log4 2 x log109 and z = log100.4 , find :
(i) x - y - z
(ii) 13x - y - z

योग

उत्तर

(i) x - y - z

= log1012 - log42 x log109 - log100.4

= log10( 4 x 3 ) - log42 x log109 - log100.4

= log104 + log103 - log42 x 2log103 - log10`( 4/10 )`

= log104 + log103 - `(log_10 2)/(2log_10 2)` x 2log103 - log104 + log1010
= log104 + log103 - `[ 2log_10 3 ]/2`- log104 + 1
= 1

(ii) 13x - y - z = 131 = 13.

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More About Logarithm
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Logarithms - Exercise 8 (D) [पृष्ठ १११]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 8 Logarithms
Exercise 8 (D) | Q 17 | पृष्ठ १११
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