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प्रश्न
Given x = log1012 , y = log4 2 x log109 and z = log100.4 , find :
(i) x - y - z
(ii) 13x - y - z
उत्तर
(i) x - y - z
= log1012 - log42 x log109 - log100.4
= log10( 4 x 3 ) - log42 x log109 - log100.4
= log104 + log103 - log42 x 2log103 - log10`( 4/10 )`
= log104 + log103 - `(log_10 2)/(2log_10 2)` x 2log103 - log104 + log1010
= log104 + log103 - `[ 2log_10 3 ]/2`- log104 + 1
= 1
(ii) 13x - y - z = 131 = 13.
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