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प्रश्न
Find x, if : logx (5x - 6) = 2
उत्तर
logx (5x - 6) = 2
⇒ 5x - 6 = x2 ...[ Removing logarithm ]
⇒ x2 - 5x + 6 = 0
⇒ x2 - 3x - 2x + 6 = 0
⇒ x( x - 3 ) - 2( x - 3 ) = 0
⇒ ( x - 2 )( x - 3 ) = 0
∴ x = 2, 3.
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