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प्रश्न
Prove that (log a)2 - (log b)2 = `"log"("a"/"b")."log"("ab")`
उत्तर
L.H.S.
= (log a)2 - (log b)2
= (log a + log b)(log a - log b) ...{using identity m2 - n2 = (m + n)(m - n)}
= `"log"("ab")"log"("a"/"b")`
= `"log"("a"/"b")."log"("ab")`
= R.H.S.
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