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प्रश्न
Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code:
| Column I (Complex ion) | Column II (Hybridisation, number of unpaired electrons) |
| A. \[\ce{[Cr(H2O)6]^{3+}}\] | 1. dsp2, 1 |
| B. \[\ce{[Co(CN)4]^{2-}}\] | 2. sp3d2, 5 |
| C. \[\ce{[Ni(NH3)6]^{2+}}\] | 3. d2sp3, 3 |
| D. \[\ce{[MnF6]^{4-}}\] | 4. sp3, 4 |
| 5. sp3d2, 2 |
विकल्प
A - (3), B - (1), C - (5), D - (2)
A - (4), B - (3), C - (2), D - (1)
A - (3), B - (2), C - (4), D - (1)
A - (4), B - (1), C - (2), D - (3)
उत्तर
A - (3), B - (1), C - (5), D - (2)
Explanation:
| Column I (Complex ion) | Column II (Hybridisation, number of unpaired electrons) |
| A. \[\ce{[Cr(H2O)6]^{3+}}\] | 3. d2sp3, 3 |
| B. \[\ce{[Co(CN)4]^{2-}}\] | 1. dsp2, 1 |
| C. \[\ce{[Ni(NH3)6]^{2+}}\] | 5. sp3d2, 2 |
| D. \[\ce{[MnF6]^{4-}}\] | 2. sp3d2, 5 |
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Crystal field splitting by various ligands Metal complexes show different colours due to d-d transitions. The complex absorbs light of specific wavelength to promote the electron from t2g to eg level. The colour of the complex is due to the transmitted light, which is complementary of the colour absorbed. The wave number of light absorbed by different complexes of Cr ion are given below:
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(a) Out of ligands "A", "B", "C" and "D", which ligand causes maximum crystal field splitting? Why?
OR
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