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Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code: Column I (Complex ion) Column I - Chemistry

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Question

Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code:

Column I (Complex ion) Column II (Hybridisation, number of unpaired electrons)
A. \[\ce{[Cr(H2O)6]^{3+}}\] 1. dsp2, 1
B. \[\ce{[Co(CN)4]^{2-}}\] 2. sp3d2, 5
C. \[\ce{[Ni(NH3)6]^{2+}}\] 3. d2sp3, 3
D. \[\ce{[MnF6]^{4-}}\] 4. sp3, 4
  5. sp3d2, 2

Options

  • A - (3), B - (1), C - (5), D - (2)

  • A - (4), B - (3), C - (2), D - (1)

  • A - (3), B - (2), C - (4), D - (1)

  • A - (4), B - (1), C - (2), D - (3)

MCQ

Solution

A - (3), B - (1), C - (5), D - (2)

Explanation:

Column I (Complex ion) Column II (Hybridisation, number of unpaired electrons)
A. \[\ce{[Cr(H2O)6]^{3+}}\] 3. d2sp3, 3
B. \[\ce{[Co(CN)4]^{2-}}\] 1. dsp2, 1
C. \[\ce{[Ni(NH3)6]^{2+}}\] 5. sp3d2, 2
D. \[\ce{[MnF6]^{4-}}\] 2. sp3d2, 5
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Chapter 9: Coordination Compounds - Exercises [Page 125]

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NCERT Exemplar Chemistry [English] Class 12
Chapter 9 Coordination Compounds
Exercises | Q IV. 38. | Page 125

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