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प्रश्न
Obtain an expression for the self-inductance of a solenoid.
उत्तर
- Consider a current I established in the windings (turns) of a long solenoid. The current produces a magnetic flux `phi_"B"` through the central region.
- The inductance of the solenoid is given by,
L = `("N"phi_"B")/"I",`
where N = the number of turns,
ΦB = magnetic flux linkage. - The flux linkage for a length l near the middle of the solenoid is,
NΦB = (nl) `(vec"B". vec"A")` = nlBA, (for θ = 0°),
where n = the number of turns per unit length,
B = magnetic field
A = the cross-sectional area of the solenoid. - The magnetic field inside the solenoid is given as, B = `mu_0"ni"`
- Hence, L = `("N"phi_"B")/"i"`
= `(("nl")"BA")/"i"`
= `("nl"(mu_0"ni")"A")/"i"`
∴ L = μ0n2lA
where, Al is the interior volume of solenoid.
संबंधित प्रश्न
Explain the phenomenon of self induction
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The currents flowing in the two coils of self-inductance L1 = 16 mH and L2 = 12 mH are increasing at the same rate. If the power supplied to the two coil is equal, find the ratio of the currents ?
Derive the expression for the self-inductance of a long solenoid of cross sectional area A and length l, having n turns per unit length.
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Define self inductance. Write its S.I. units.
Consider the self-inductance per unit length of a solenoid at its centre and that near its ends. Which of the two is greater?
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(a) magnetic field at the centre
(b) magnetic flux linked with the solenoid
(c) self-inductance of the solenoid
(d) rate of Joule heating.
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A coil having inductance 2.0 H and resistance 20 Ω is connected to a battery of emf 4.0 V. Find (a) the current at the instant 0.20 s after the connection is made and (b) the magnetic field energy at this instant.
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What are the values of the self-induced emf in the circuit of the previous problem at the times indicated therein?
Answer the following question.
When an inductor is connected to a 200 V dc voltage, a current at 1A flows through it. When the same inductor is connected to a 200 V, 50 Hz ac source, only 0.5 A current flows. Explain, why? Also, calculate the self-inductance of the inductor.
Choose the correct option
A current through a coil of self-inductance 10 mH increases from 0 to 1 A in 0.1 s. What is the induced emf in the coil?
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The self-inductance associated with a coil is independent of ______.
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(Assume that, l = current passes through the turns, µ0 = Permeability of vacuum)
Calculate the self-inductance of a coil using the following data obtained when an AC source of frequency `(200/pi)` Hz and a DC source are applied across the coil.
AC Source | ||
S.No. | V (volts) | I (A) |
1 | 3.0 | 0.5 |
2 | 6.0 | 1.0 |
3 | 9.0 | 1.5 |
DC Source | ||
S.No. | V (volts) | I (A) |
1 | 4.0 | 1.0 |
2 | 6.0 | 1.5 |
3 | 8.0 | 2.0 |
A current of 1A flows through a coil when it is connected across a DC battery of 100V. If the DC battery is replaced by an AC source of 100 V and angular frequency of 100 rad s-1, the current reduces to 0.5 A. Find
- the impedance of the circuit.
- self-inductance of coil.
- Phase difference between the voltage and the current.
State the factors on which the magnetic coupling coefficient of two coils depends.
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What is meant by magnetic coupling coefficient?