Advertisements
Advertisements
प्रश्न
Solve, graphically, the following pairs of equation :
2x + y = 23
4x - y = 19
उत्तर
2x + y = 23 ⇒ y = 23 - 2x
The table for y = 23 - 2x is
X | 5 | 10 | 15 |
Y | 13 | 3 | - 7 |
Also, we have
4x - y = 19 ⇒ y = 4x - 19
The table for y = 4x - 19 is
X | 3 | 4 | 6 |
Y | - 7 | - 3 | 5 |
Plotting the points we get the following required graph:
From the above graph, it is clear that the two lines y = 23 - 2x and y = 4x - 19 intersect at the point (7, 9)
APPEARS IN
संबंधित प्रश्न
Yamini and Fatima, two students of Class IX of a school, together contributed Rs. 100 towards the Prime Minister’s Relief Fund to help the earthquake victims. Write a linear equation which satisfies this data. (You may take their contributions as Rs. x and Rs. y.) Draw the graph of the same.
Draw the graph for the equation, given below :
x + 5 = 0
Draw the graph for the equation, given below :
2x + 3y = 0
Draw the graph for the equation, given below :
x - 5y + 4 = 0
Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(1)/(3) x +(1)/(5) y = 1`.
Draw the graph of the equation 2x - 3y - 5 = 0
From the graph, find:
(i) x1, the value of x, when y = 7
(ii) x2, the value of x, when y = - 5.
A straight line passes through the points (2, 4) and (5, - 2). Taking 1 cm = 1 unit; mark these points on a graph paper and draw the straight line through these points. If points (m, - 4) and (3, n) lie on the line drawn; find the values of m and n.
Use the graphical method to find the value of k, if:
(5, k - 2) lies on the straight line x - 2y + 1 = 0
Draw the graphs of the following linear equations:
3x + 2y - 6 = 0
Draw the graph of y = 2x + 5