Advertisements
Advertisements
प्रश्न
State Biot-Savart law.
A current I flows in a conductor placed perpendicular to the plane of the paper. Indicate the direction of the magnetic field due to a small element d `vecl` at point P situated at distance `vecr` from the element as shown in the figure.
उत्तर
Biot-Savart’s law states that the magnitude of the magnetic field dB is proportional to the current I, the element`|dl|`, and inversely proportional to the square of the distance r.
The direction of magnetic field is along the negative X-direction.
APPEARS IN
संबंधित प्रश्न
State Biot – Savart law.
Express Biot – Savart law in the vector form.
What does a toroid consist of? Find out the expression for the magnetic field inside a toroid for N turns of the coil having the average radius r and carrying a current I. Show that the magnetic field in the open space inside and exterior to the toroid is zero.
An alpha particle is projected vertically upward with a speed of 3.0 × 104 km s−1 in a region where a magnetic field of magnitude 1.0 T exists in the direction south to north. Find the magnetic force that acts on the α-particle.
A wire of length l is bent in the form of an equilateral triangle and carries an electric current i. (a) Find the magnetic field B at the centre. (b) If the wire is bent in the form of a square, what would be the value of B at the centre?
A wire of length l is bent in the form of an equilateral triangle and carries an electric current i. Find the magnetic field B at the centre.
Two concentric circular loops of radius 1 cm and 20 cm are placed coaxially.
(i) Find mutual inductance of the arrangement.
(ii) If the current passed through the outer loop is changed at a rate of 5 A/ms, find the emf induced in the inner loop. Assume the magnetic field on the inner loop to be uniform.
Biot-Sawart law indicates that the moving electrons (velocity `overset(->)("v")`) produce a magnetic field B such that
Using Biot-Savart law, show that magnetic flux density 'B' at the centre of a current carrying circular coil of radius R is given by: `B = ("μ"_0I)/(2R)` where the terms have their usual meaning.
