Advertisements
Advertisements
प्रश्न
State Biot – Savart law.
उत्तर
According to Biot–Savart’s law, the magnitude of the magnetic field dB is proportional to the current I and the element length dl, and inversely proportional to the square of the distance r.
APPEARS IN
संबंधित प्रश्न
Express Biot – Savart law in the vector form.
A wire of length l is bent in the form of an equilateral triangle and carries an electric current i. (a) Find the magnetic field B at the centre. (b) If the wire is bent in the form of a square, what would be the value of B at the centre?
Derive the expression for the magnetic field due to a current-carrying coil of radius r at a distance x from the center along the X-axis.
Biot-Savart law indicates that the moving electrons (velocity v) produce a magnetic field B such that ______.
- both are long range and inversely proportional to the square of distance from the source to the point of interest.
-
both are linear in source.
-
both are produced by scalar sources.
-
both follow principle of superposition.
Biot-Savart law indicates that the moving electrons velocity (V) produce a magnetic field B such that ______.
A circular loop of radius 0.3 cm lies parallel to much bigger circular of radius 20 cm. The centre of the small loop is on the axis of the bigger loop. The distance between their centres is 15 cm. If a current of 2.0 A flows through the smaller loop, then the flux linked with the bigger loop is ______.
The magnetic field at any point on the axis of a current element is ______
A current carrying loop consists of 3 identical quarter circles of radius R, lying in the positive quadrants of the x-y, y-z and z-x planes with their centres at the origin, joined together. Find the direction and magnitude of B at the origin.
Using Biot-Savart law, show that magnetic flux density 'B' at the centre of a current carrying circular coil of radius R is given by: `B = ("μ"_0I)/(2R)` where the terms have their usual meaning.
