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प्रश्न
Give the formula and describe the structure of a noble gas species which is isostructural with:
`IBr_2^(-)`
उत्तर १
XeF2 is isoelectronic to `IBr_2^(-)` and has a linear structure.
उत्तर २
IBr2–: In IBr2–, central atom I has eight electrons. Two of these are utilized in forming two single bonds with two Br atom. Six remaining electrons constitutes three lone pairs. It is arranged in linear structure.
IBr2– has 22 valence electrons. A noble gas species having 22 valence electrons is XeF2 (8+2 x 7=22).
XeF2 is also linear.
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| List - I | List - II | ||
| (Species) | (Number of lone pairs of electrons on the central atom) |
||
| (A) | XeF2 | (i) | 0 |
| (B) | XeO2F2 | (ii) | 1 |
| (C) | XeO3F2 | (iii) | 2 |
| (D) | XeF4 | (iv) | 3 |
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\[\ce{XeF6 + H2O ->[Partial][Hydrolysis] \underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}}\]
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