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प्रश्न
Suggest a suitable physical situation for the following graphs:
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संबंधित प्रश्न
The figure shows the x-t plot of one-dimensional motion of a particle. Is it correct to say from the graph that the particle moves in a straight line for t < 0 and on a parabolic path for t > 0? If not, suggest a suitable physical context for this graph.
A police van moving on a highway with a speed of 30 km h–1 fires a bullet at a thief’s car speeding away in the same direction with a speed of 192 km h–1. If the muzzle speed of the bullet is 150 m s–1, with what speed does the bullet hit the thief’s car? (Note: Obtain that speed which is relevant for damaging the thief’s car).
Two projectiles A and B are projected with angle of projection 15° for the projectile A and 45° for the projectile B. If RA and RB be the horizontal range for the two projectiles, then
A particle moves along the X-axis as x = u (t − 2 s) + a (t − 2 s)2.
(a) the initial velocity of the particle is u
(b) the acceleration of the particle is a
(c) the acceleration of the particle is 2a
(d) at t = 2 s particle is at the origin.
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In the following figure Shows the graph of velocity versus time for a particle going along the X-axis. Find the acceleration
Refer to the graphs in figure. Match the following.
| Graph | Characteristic |
(a)  |
(i) has v > 0 and a < 0 throughout. |
(b)  |
(ii) has x > 0 throughout and has a point with v = 0 and a point with a = 0. |
(c)  |
(iii) has a point with zero displacement for t > 0. |
(d)  |
(iv) has v < 0 and a > 0. |
A man runs across the roof-top of a tall building and jumps horizontally with the hope of landing on the roof of the next building which is of a lower height than the first. If his speed is 9 m/s, the (horizontal) distance between the two buildings is 10 m and the height difference is 9 m, will he be able to land on the next building? (take g = 10 m/s2)
A person moved from A to B on a circular path as shown in figure. If the distance travelled by him is 60 m, then the magnitude of displacement would be: (Given cos135° = - 0.7)
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