हिंदी

The Angle of Elevation of a Tower from a Point 200 M from Its Base is θ, When Tan θ = 2 5 . the Angle of Elevation of this Tower from a Point 120m from Its Base is φ . Calculate the - Mathematics

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प्रश्न

The angle of elevation of a tower from a point 200 m from its base is θ, when `tan θ = 2/5`. The angle of elevation of this tower from a point 120m from its base is `Φ`. Calculate the height of tower and the value of `Φ`. 

योग

उत्तर

Let OT be the tower .

A and B be the two points from where the angle of elevation to the top of the tower is measured.

In ΔAOT,

`"OT"/"OA" = tanθ`

⇒ `"h"/200 = 2/5`

⇒ h = 80  ...(1)

Thus , the height of the tower is 80 m.

In ΔBOT,

`"OT"/"OB" = tanΦ`

⇒ `"h"/120 = tanΦ`

⇒ `80/120 = tanΦ`   [Using (1)]

⇒ `2/3 = tanΦ`

From the table , we get `Φ = 34^circ`.

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Heights and Distances - Solving 2-D Problems Involving Angles of Elevation and Depression Using Trigonometric Tables
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 22: Heights and Distances - Exercise

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 22 Heights and Distances
Exercise | Q 32

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