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प्रश्न
The annual profits earned by 30 shops of a shopping complex in a locality give rise to the following distribution:
Profit (in lakhs in Rs) | Number of shops (frequency) |
More than or equal to 5 More than or equal to 10 More than or equal to 15 More than or equal to 20 More than or equal to 25 More than or equal to 30 More than or equal to 35 |
30 28 16 14 10 7 3 |
Draw both ogives for the above data and hence obtain the median.
उत्तर
Firstly, we prepare the cumulative frequency table for less than type.
Profit (In lakh in Rs.) |
No. of shops (frequency) |
Profit (less than) |
Cumulative frequency |
Suitable points |
5-10 | 2 | 10 | 2 | (10, 2) |
10-15 | 12 | 15 | 14 | (15, 14) |
15-20 | 2 | 20 | 16 | (20, 16) |
20-25 | 4 | 25 | 20 | (25, 20) |
25-30 | 3 | 30 | 23 | (30, 23) |
30-35 | 4 | 35 | 27 | (35, 27) |
35-40 | 3 | 40 | 30 | (40, 30) |
Again, prepare the cumulative frequency table for more than type.
Profit (In lakh in Rs.) |
No. of shops (frequency) |
Profit (more than) |
Cumulative |
Suitable |
5-10 | 2 | 5 | 30 | (5, 30) |
10-15 | 12 | 10 | 28 | (10, 28) |
15-20 | 2 | 15 | 16 | (15, 16) |
20-25 | 4 | 20 | 14 | (20, 14) |
25-30 | 3 | 25 | 10 | (25, 10) |
30-35 | 4 | 30 | 7 | (30, 7) |
35-40 | 3 | 35 | 3 | (35, 3) |
Now, “more than ogive” and “less than ogive” can be drawn as follows:
The x-coordinate of the point of intersection of the “more-than ogive” and “less-than ogive” gives the median of the given distribution..
So, the corresponding median is Rs 17.5 lakh.
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संबंधित प्रश्न
Draw an ogive by less than method for the following data:
No. of rooms: | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
No. of houses: | 4 | 9 | 22 | 28 | 24 | 12 | 8 | 6 | 5 | 2 |
The marks scored by 750 students in an examination are given in the form of a frequency distribution table:
Marks | No. of students |
600 - 640 | 16 |
640 - 680 | 45 |
680 - 720 | 156 |
720 - 760 | 284 |
760 - 800 | 172 |
800 - 840 | 59 |
840 - 880 | 18 |
Draw an ogive to represent the following frequency distribution:
Class-interval: | 0 - 4 | 5 - 9 | 10 - 14 | 15 - 19 | 20 - 24 |
Frequency: | 2 | 6 | 10 | 5 | 3 |
Draw a cumulative frequency curve (ogive) for the following distributions:
Class Interval | 10 – 15 | 15 – 20 | 20 – 25 | 25 – 30 | 30 – 35 | 35 – 40 |
Frequency | 10 | 15 | 17 | 12 | 10 | 8 |
Construct a frequency distribution table for the following distributions:
Marks (less than) | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 | 90 | 100 |
Cumulative frequency | 0 | 7 | 28 | 54 | 71 | 84 | 105 | 147 | 180 | 196 | 200 |
Construct a frequency distribution table for the following distributions:
Marks (more than) | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 | 90 | 100 |
Cumulative frequency | 100 | 87 | 65 | 55 | 42 | 36 | 31 | 21 | 18 | 7 | 0 |
Draw an ogive for the following :
Marks obtained | Less than 10 | Less than 20 | Less than 30 | Less than 40 | Less than 50 |
No. of students | 8 | 22 | 48 | 60 | 75 |
Draw an ogive for the following :
Marks obtained | More than 10 | More than 20 | More than 30 | More than 40 | More than 50 |
No. of students | 8 | 25 | 38 | 50 | 67 |
The following is the frequency distribution with unknown frequencies :
Class | 60-70 | 70-80 | 80-90 | 90-100 | Total |
frequency | `"a"/2` | `(3"a")/2` | 2a | a | 50 |
Find the value of a, hence find the frequencies. Draw a histogram and frequency polygon on the same coordinate system.
The frequency distribution of scores obtained by 230 candidates in a medical entrance test is as ahead:
Cost of living Index | Number of Months |
400 - 450 | 20 |
450 - 500 | 35 |
500 - 550 | 40 |
550 - 600 | 32 |
600 - 650 | 24 |
650 - 700 | 27 |
700 - 750 | 18 |
750 - 800 | 34 |
Total | 230 |
Draw a cummulative polygon (ogive) to represent the above data.