हिंदी

The future amount, A = ₹ 10,00,000 Period, n = 20, r = 5%, (1.025)20 = 1.675 A = CI[(1+i)n-1] I = 5200 = □ as interest is calculated semi-annually A = 10,00,000 = CI[(1+i)n-1] 10,00,000 = C0.025[(1+0 - Mathematics and Statistics

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प्रश्न

The future amount, A = ₹ 10,00,000

Period, n = 20, r = 5%, (1.025)20 = 1.675

A = `"C"/"I" [(1 + "i")^"n" - 1]`

I = `5/200` = `square` as interest is calculated semi-annually

A = 10,00,000 = `"C"/"I" [(1 + "i")^"n" - 1]`

10,00,000 = `"C"/0.025 [(1 + 0.025)^square - 1]`

= `"C"/0.025 [1.675 - 1]`

10,00,000 = `("C" xx 0.675)/0.025`

C = ₹ `square`

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उत्तर

The future amount, A = ₹ 10,00,000

Period, n = 20, r = 5%, (1.025)20 = 1.675

A = `"C"/"I" [(1 + "i")^"n" - 1]`

I = `5/200` = 0.025 as interest is calculated semi-annually

A = 10,00,000 = `"C"/"I" [(1 + "i")^"n" - 1]`

10,00,000 = `"C"/0.025 [(1 + 0.025)^20 - 1]`

= `"C"/0.025[(1.025)^20 - 1]`

= `"C"/0.025 [1.675 - 1]`

10,00,000 = `("C" xx 0.675)/0.025`

C = `(10,00,000 xx 0.025)/0.675`

C = ₹ 37037.03

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Annuity
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2.2: Insurance and Annuity - Q.5

संबंधित प्रश्न

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Find the accumulated value of annuity due of ₹1,000 p.a. for 3 years at 10% p.a. compounded annually. [Given (1.1)3 = 1.331]


For an annuity immediate paid for 3 years with interest compounded at 10% p.a., the present value is ₹24,000. What will be the accumulated value after 3 years? [Given (1.1)3 = 1.331]


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If payments of an annuity fall due at the end of every period, the series is called annuity __________.


Solve the following :

Find the rate of interest compounded annually if an ordinary annuity of ₹20,000 per year amounts to ₹41,000 in 2 years.


Solve the following :

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For an annuity due, C = ₹ 2000, rate = 16% p.a. compounded quarterly for 1 year

∴ Rate of interest per quarter = `square/4` = 4

⇒ r = 4%

⇒ i = `square/100 = 4/100` = 0.04

n = Number of quarters

= 4 × 1

= `square`

⇒ P' = `(C(1 + i))/i [1 - (1 + i)^-n]`

⇒ P' = `(square(1 + square))/0.04 [1 - (square + 0.04)^-square]`

= `(2000(square))/square [1 - (square)^-4]`

= 50,000`(square)`[1 – 0.8548]

= ₹ 7,550.40


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