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Find the accumulated (future) value of annuity of ₹800 for 3 years at interest rate 8% compounded annually. [Given (1.08)3 = 1.2597] - Mathematics and Statistics

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प्रश्न

Find the accumulated (future) value of annuity of ₹ 800 for 3 years at interest rate 8% compounded annually. [Given (1.08)3 = 1.2597]

योग

उत्तर

Given, C = ₹ 800, n = 3 years, r = 8% p.a.

i = `"r"/(100) = (8)/(100)` = 0.08

Now, A = `"C"/"i"[(1 + "i")^"n" - 1]`

∴ A = `(800)/(0.08)[(1 + 0.08)^3 - 1]`

= `(800 xx 100)/(0.08 xx 100)[(1.08)^3 - 1]`

= `(80000)/8(1.2597 - 1)`

= 10,000 × 0.2597

= 2,597

∴ Accumulate (future) value of annuity is ₹ 2,597.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Insurance and Annuity - Exercise 2.2 [पृष्ठ २७]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] 12 Standard HSC Maharashtra State Board
अध्याय 2 Insurance and Annuity
Exercise 2.2 | Q 1.01 | पृष्ठ २७

संबंधित प्रश्न

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A person sets up a sinking fund in order to have ₹ 1,00,000 after 10 years. What amount should be deposited bi-annually in the account that pays him 5% p.a. compounded semi-annually? [Given (1.025)20 = 1.675]


Choose the correct alternative :

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Annuity contingent begins and ends on certain fixed dates.


State whether the following is True or False :

Sinking fund is set aside at the beginning of a business.


Solve the following :

Find the rate of interest compounded annually if an ordinary annuity of ₹20,000 per year amounts to ₹41,000 in 2 years.


Solve the following :

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Multiple choice questions:

The present value of an immediate annuity of ₹ 10,000 paid each quarter for four quarters at 16% p.a. compounded quarterly is ______


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An annuity where payments continue forever is called perpetuity


A company decides to set aside a certain sum at the end of each year to create a sinking fund, which should amount to ₹ 4 lakhs in 4 years at 10% p.a. Find the amount to be set aside each year?
[Given (1.1)4 = 1.4641]


The future amount, A = ₹ 10,00,000

Period, n = 20, r = 5%, (1.025)20 = 1.675

A = `"C"/"I" [(1 + "i")^"n" - 1]`

I = `5/200` = `square` as interest is calculated semi-annually

A = 10,00,000 = `"C"/"I" [(1 + "i")^"n" - 1]`

10,00,000 = `"C"/0.025 [(1 + 0.025)^square - 1]`

= `"C"/0.025 [1.675 - 1]`

10,00,000 = `("C" xx 0.675)/0.025`

C = ₹ `square`


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