Advertisements
Advertisements
प्रश्न
The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of transition element, which shows highest magnetic moment.
विकल्प
3d7
3d5
3d8
3d2
उत्तर
3d5
Explanation:
The greater the number of unpaired electron, the higher will be its value of magnetic moment. Since, 3d5 has 5 unpaired electrons hence highest magnetic moment.
`mu = sqrt(5(5 + 2))`
= `sqrt(35)`
= 5.95 BM
APPEARS IN
संबंधित प्रश्न
For M2+/M and M3+/M2+ systems, the EΘ values for some metals are as follows:
| Cr2+/Cr | −0.9 V |
| Mn2+/Mn | −1.2 V |
| Fe2+/Fe | −0.4 V |
| Cr3/Cr2+ | −0.4 V |
| Mn3+/Mn2+ | +1.5 V |
| Fe3+/Fe2+ | +0.8 V |
Use this data to comment upon:
The stability of Fe3+ in acid solution as compared to that of Cr3+ or Mn3+.
How would you account for the following?
Zr (Z = 40) and Hf (Z = 72) have almost identical radii.
Electronic configuration of a transition element X in +3 oxidation state is [Ar]3d5. What is its atomic number?
Highest oxidation state of manganese in fluoride is \[\ce{+4 (MnF4)}\] but highest oxidation state in oxides is \[\ce{+7 (Mn2O7)}\] because ______.
A violet compound of manganese (A) decomposes on heating to liberate oxygen and compounds (B) and (C) of manganese are formed. Compound (C) reacts with KOH in the presence of potassium nitrate to give compound (B). On heating compound (C) with conc. \[\ce{H2SO4}\] and \[\ce{NaCl}\], chlorine gas is liberated and a compound (D) of manganese along with other products is formed. Identify compounds A to D and also explain the reactions involved.
If enthalpies of formation of C2H4(g), CO2(g) and H2O(l) at 25°C and 1 atm pressure are 52, – 394 and – 286 kJ/mol respectively, the change in ethalpy for combustion of C2H4 is equal to
The orientation of an atomic orbital is governed by
Agcl is soluble in NH4OH. The solubility is due to the information of:-
Account for the following:
Ce4+ is a strong oxidising agent.
Explain the magnetic properties of d-block (or transition) elements.
