हिंदी

The manufacturing company produces x items at the total cost of ₹ 180 + 4x. The demand function for this product is P = (240 − 𝑥). Find x for which profit is increasing - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

The manufacturing company produces x items at the total cost of ₹ 180 + 4x. The demand function for this product is P = (240 − 𝑥). Find x for which profit is increasing

योग

उत्तर

Now, Profit = Revenue − Total cost

∴ π = R − C

= 240x − x2 − (180 + 4x)

= 240x − x2 − 180 − 4x

∴ π = − x2 + 236x − 180 

dπdx = −2x + 236 = 2(− x + 118)

Since profit is an increasing function, dπdx > 0

∴ 2(−x + 118) > 0

∴ − x + 118 > 0

∴ 118 > x

∴ x < 118

∴ The profit is increasing for x < 118.

shaalaa.com
Application of Derivatives to Economics
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1.4: Applications of Derivatives - Q.5

संबंधित प्रश्न

Find the elasticity of demand, if the marginal revenue is 50 and price is Rs 75.


The manufacturing company produces x items at the total cost of ₹ 180 + 4x. The demand function for this product is P = (240 – x). Find x for which revenue is increasing


The total cost of manufacturing x articles C = 47x + 300x2 – x4 . Find x, for which average cost is decreasing


Find the price, if the marginal revenue is 28 and elasticity of demand is 3.


If the demand function is D = (p+6p3), find the elasticity of demand at p = 4.


Find the price for the demand function D = (2p+33p-1), when elasticity of demand is 1114.


If the demand function is D = 50 – 3p – p2. Find the elasticity of demand at p = 5 comment on the result


If the demand function is D = 50 – 3p – p2. Find the elasticity of demand at p = 2 comment on the result


For the demand function D = 100 – p22. Find the elasticity of demand at p = 10 and comment on the results.


For the demand function D = 100 – p22. Find the elasticity of demand at p = 6 and comment on the results.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which revenue is increasing.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which profit is increasing.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which also find an elasticity of demand for price 80.


Find MPC, MPS, APC and APS, if the expenditure Ec of a person with income I is given as Ec = (0.0003) I2 + (0.075) I ; When I = 1000.


Fill in the blank:

A road of 108 m length is bent to form a rectangle. If the area of the rectangle is maximum, then its dimensions are _______.


If the elasticity of demand η = 1, then demand is ______.


If 0 < η < 1, then the demand is ______.


If the average revenue is 45 and elasticity of demand is 5, then marginal revenue is ______.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price per item is given as p = 120 – x. Find the value of x for which profit is increasing

Solution: Total cost C = 40 + 2x and Price p = 120 − x

Profit π = R – C

∴ π =

Differentiating w.r.t. x,

dπdx =

Since Profit is increasing,

dπdx > 0

∴ Profit is increasing for


If elasticity of demand η = 0 then demand is ______.


If f(x) = x3 – 3x2 + 3x – 100, x ∈ R then f"(x) is ______.


If 0 < η < 1 then the demand is ______.


In a factory, for production of Q articles, standing charges are ₹500, labour charges are ₹700 and processing charges are 50Q. The price of an article is 1700 - 3Q. Complete the following activity to find the values of Q for which the profit is increasing.

Solution: Let C be the cost of production of Q articles.

Then C = standing charges + labour charges + processing charges

∴ C =  

Revenue R = P·Q = (1700 - 3Q)Q = 1700Q- 3Q2

Profit π=R-C=

 Differentiating w.r.t. Q, we get

dπdQ=

If profit is increasing , then dπdQ>0

Q< 

Hence, profit is increasing for Q< 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×
Our website is made possible by ad-free subscriptions or displaying online advertisements to our visitors.
If you don't like ads you can support us by buying an ad-free subscription or please consider supporting us by disabling your ad blocker. Thank you.