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प्रश्न
The pressure-volume work for an ideal gas can be calculated by using the expression w = `- int_(v_i)^(v_f) p_(ex) dV`. The work can also be calculated from the pV– plot by using the area under the curve within the specified limits. When an ideal gas is compressed (a) reversibly or (b) irreversibly from volume Vi to Vf. choose the correct option.
विकल्प
w (reversible) = w (irreversible)
w (reversible) < w (irreversible)
w (reversible) > w (irreversible)
w (reversible) = w (irreversible) + `P_(ex).∆V`
उत्तर
w (reversible) < w (irreversible)
Explanation:
Area under the curve is greater in irreversible compression than that of reversible compression.
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संबंधित प्रश्न
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In which of the processes potential energy/enthalpy change is contributing factor to the spontaneity?
Match the following :
| A | B |
| (i) Adiabatic process | (a) Heat |
| (ii) Isolated system | (b) At constant volume |
| (iii) Isothermal change | (c) First law of thermodynamics |
| (iv) Path function | (d) No exchange of energy and matter |
| (v) State function | (e) No transfer of heat |
| (vi) ΔU = q | (f) Constant temperature |
| (vii) Law of conservation of energy | (g) Internal energy |
| (viii) Reversible process | (h) Pext = o |
| (ix) Free expansion | (i) At constant pressure |
| (x) ΔH = q | (j) Infinitely slow process which proceeds through a series of equilibrium states. |
| (xi) Intensive property | (k) Entropy |
| (xii) Extensive property | (l) Pressure |
| (m) Specific heat |
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