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The radius of an air bubble is increasing at the rate 12 cm/s. At what rate is the volume of the bubble increasing when the radius is 1 cm? - Mathematics

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प्रश्न

The radius of an air bubble is increasing at the rate  `1/2`  cm/s. At what rate is the volume of the bubble increasing when the radius is 1 cm?

योग

उत्तर

Let the radius of the bubble = r and the volume of the bubble

`"V" = 4/3 pi"r"^3`

According to the question, `(dr)/dt = 1/2` cm/s

Again `(dV)/dt = d/dt (4/3 pir^3)`

`= d/dt (4/3 pir^3) * (dr)/dt `

Or `(dV)/dt 4pir^2 * 1/2 = 2 pir^2` cm3/s

`therefore ((dV)/dt)_(r = 1) = 2pi (1)^2`

`= 2 pi` cm3/s

Hence, the rate of increase of the volume of the bubble is 2π cm3/s.

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अध्याय 6: Application of Derivatives - Exercise 6.1 [पृष्ठ १९८]

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एनसीईआरटी Mathematics [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.1 | Q 12 | पृष्ठ १९८

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