Advertisements
Advertisements
प्रश्न
Three of the exterior angles of a hexagon are 40°, 51 ° and 86°. If each of the remaining exterior angles is x°, find the value of x.
उत्तर
The sum of all exterior angles of any polygon is always: 360∘
The total of the six exterior angles is: 40∘ + 51∘ + 86∘ + x + x + x = 360∘
Simplify: 177∘ + 3x = 360∘
Subtract 177∘ from both sides: 3x = 183∘
Divide by 3: `x=(183°)/3 = 61°`
Each of the remaining three exterior angles is: 61∘
APPEARS IN
संबंधित प्रश्न
Find the number of sides in a regular polygon, if its interior angle is: `1 1/5` of a right angle
Is it possible to have a regular polygon whose interior angle is:
138°
Is it possible to have a regular polygon whose each exterior angle is: 80°
AB, BC and CD are three consecutive sides of a regular polygon. If angle BAC = 20° ; find :
(i) its each interior angle,
(ii) its each exterior angle
(iii) the number of sides in the polygon.
Two alternate sides of a regular polygon, when produced, meet at the right angle. Calculate the number of sides in the polygon.
If the difference between the exterior angle of a 'n' sided regular polygon and an (n + 1) sided regular polygon is 12°, find the value of n.
The ratio between the number of sides of two regular polygons is 3 : 4 and the ratio between the sum of their interior angles is 2 : 3. Find the number of sides in each polygon.
Find the number of sides in a regular polygon, if its interior angle is: 150°
Find a number of side in a regular polygon, if it exterior angle is: 30°.
Is it possible to have a regular polygon whose exterior angle is: 36°