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प्रश्न
Two periodic waves of amplitudes A1 and A2 pass thorough a region. If A1 > A2, the difference in the maximum and minimum resultant amplitude possible is
विकल्प
2A1
2A2
A1 + A2
A1 − A2
उत्तर
2A2
We know resultant amplitude is given by
\[A_{net} = \sqrt{A_1^2 + A_2^2 + 2 A_1 A_2 \cos\phi}\] For maximum resultant amplitude \[A_\max = A_1 + A_2\] For minimum resultant amplitude \[A_\min = A_1 - A_2\]
So, the difference between Amax and Amin is
\[A_\max - A_\min = A_1 + A_2 - A_1 + A_2 = 2 A_2\]
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संबंधित प्रश्न
A wave is represented by the equation
\[y = \left( 0 \text{ cdot 001 mm }\right) \sin\left[ \left( 50 s^{- 1} \right)t + \left( 2 \cdot 0 m^{- 1} \right)x \right]\]
(a) The wave velocity = 100 m s−1.
(b) The wavelength = 2⋅0 m.
(c) The frequency = 25/π Hz.
(d) The amplitude = 0⋅001 mm.
Choose the correct option:
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