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प्रश्न
Two resistors R1 = 400Ω and R2 = 20 n are connected in parallel to a battery. If heating the power developed in R1 is 25 W. find the heating power developed in R2
उत्तर
`Power across `R_1` = 25 W
`P = V^2/R`
`25 xx 20 = V^2`
`V^2 = 500`
`V = sqrt500 V`
Power across `R_2` `P = V^2/R` = `500/400 = 1.2 W`
`V = sqrt500` as potential in parallel remain constant.
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