Advertisements
Advertisements
प्रश्न
Use graph paper for this question. Draw the graph of 2x - y - 1 = 0 and 2x + y = 9 on the same axes. Use 2 cm = 1 unit on both axes and plot only 3 points per line. Write down the coordinates of the point of intersection of the two lines.
उत्तर
2x - y - 1 = 0
⇒ 2x = y + 1
⇒ x = `(y + 1)/(2)`
This table for 2x - y - 1 = 0 is
| X | 2 | 1 | 0 |
| Y | 3 | 1 | -1 |
Also we have
2x + y = 9
⇒ 2x = 9 - y
⇒ x = `(9 - y)/(2)`
The table for 2x + y = 9 is
| X | 4 | 3 | 5 |
| Y | 1 | 3 | -1 |
Plotting the above points we get the following required graph:
From the above graph, it is clear that the two lines 2x - y - 1 = 0 and 2x + y = 9 intersect at the point (2, 5, 4)
APPEARS IN
संबंधित प्रश्न
Draw the graph of the following linear equation in two variable : ` x / 2 - y/ 3 = 2`
Draw the graph for the equation, given below :
y = 7
A straight line passes through the points (2, 4) and (5, - 2). Taking 1 cm = 1 unit; mark these points on a graph paper and draw the straight line through these points. If points (m, - 4) and (3, n) lie on the line drawn; find the values of m and n.
Solve, graphically, the following pairs of equation :
x - 5 = 0
y + 4 = 0
Solve, graphically, the following pairs of equations :
`(x + 1)/(4) = (2)/(3)(1 - 2y)`
`(2 + 5y)/(3) = x/(7) -2`
Draw the graphs of the following linear equations:
5x - 5y = 8
Draw the graph for each of the following equation: Also, find the coordinates of the points where the graph of the equation meets the coordinate axes:
`(3x + 14)/(2) = (y - 10)/(5)`
Draw the graph of the equation 4x - 3y + 12 = 0.
Also, find the area of the triangle formed by the line drawn and the coordinate axes.
Find the values.
y = 3x + 1
| x | − 1 | 0 | 1 | 2 |
| y |
The following observed values of x and y are thought to satisfy a linear equation. Write the linear equation:
| x | 6 | – 6 |
| y | –2 | 6 |
Draw the graph using the values of x, y as given in the above table. At what points the graph of the linear equation
- cuts the x-axis
- cuts the y-axis
