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प्रश्न
Using a graph paper draw a histogram of the given distribution showing the number of runs scored by 50 batsmen. Estimate the mode of the data:
| Runs scored |
3000- 4000 |
4000- 5000 |
5000- 6000 |
6000- 7000 |
7000- 8000 |
8000- 9000 |
9000- 10000 |
| No. of batsmen |
4 | 18 | 9 | 6 | 7 | 2 | 4 |
उत्तर
The histogram is as follows:
From the histogram, we have mode = 4600
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संबंधित प्रश्न
Find the mode and the median of the following frequency distribution:
| x | 10 | 11 | 12 | 13 | 14 | 15 |
| f | 1 | 4 | 7 | 5 | 9 | 3 |
If each number given in (a) is diminished by 2, find the new value of mean.
The following are the marks obtained by 70 boys in a class test:
| Marks | No. of boys |
| 30 – 40 | 10 |
| 40 – 50 | 12 |
| 50 – 60 | 14 |
| 60 – 70 | 12 |
| 70 – 80 | 9 |
| 80 – 90 | 7 |
| 90 – 100 | 6 |
Calculate the mean by:
Short-cut method
If the mean of the following observations is 54, find the value of p.
| Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
| Frequency | 7 | p | 10 | 9 | 13 |
The following table shows the frequency distribution of heights of 51 boys:
| Height (cm) | 120 | 121 | 122 | 123 | 124 |
| Frequency | 5 | 8 | 18 | 10 | 9 |
Find the mode of heights.
Find the mean of the following frequency distribution :
| Class | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
| Frequency | 8 | 6 | 12 | 11 | 13 |
Find the mean of the following frequency distribution by the step deviation method :
| Class | 100-110 | 110-120 | 120-130 | 130-140 | 140-150 |
| Frequency | 15 | 18 | 32 | 25 | 10 |
Find the mean of first ten odd natural numbers.
Find the mean of: all prime numbers upto 30
Find the mean and the median of: 1.2, 1.9, 2.2, 2.6 and 2.9
