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Using the Mathematical induction, show that for any natural number n ≥ 2,nn(1-122)(1-132)(1-142)...(1-1n2)=n+12 - Mathematics

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प्रश्न

Using the Mathematical induction, show that for any natural number n ≥ 2,
`(1 - 1/2^2)(1 - 1/3^2)(1 - 1/4^2) ... (1 - 1/"n"^2) = ("n" + 1)/2`

योग

उत्तर

Let P(n) = is the statement `(1 -1/2^2)(1 -1/3^2) .... (1 - 1/"n"^2) = ("n" + 1)/2`

Given n ≥ 2

For n = 2

L.H.S = `(1 - 1/2^2)`

= `1 - 1/4`

= `3/4`

R.H.S P(2) = `(2 + 1)/(2(2))`

= `3/4`

L.H.S = R.H.S

P(n) is true for n = 2

Assume tat P(n) is true for n = k

(i.e.) `(1 -1/2^2)(1 -1/3^2) .... (1 - 1/"k"^2) = ("k" + 1)/2` is true

To prove P(k + 1) is true

Now P(k + 1) = `"P"("k") xx("t"_("k" + 1))`

= `("k" + 1)/(2"k") xx (1 - 1/("k" + 1)^2)`

= `("k" + 1)/(2"k") xx [(("k" + 1)^2 - 1)/("k" + 1)^2]`

= `("k" + 1)/(2"k") xx ("k"^2 + 2"k" + 1 - 1)/("k" + 1)^2`

= `("k" + 1)/(2"k") xx ("k"("k" + 2))/("k" + 1)^2`

= `("k" + 2)/(2("k" + 1))`

= `(("k" + 1 + 1))/(2("k" + 1))`

⇒ P(k + 1) is true when P(k) is true so by the principle of mathematical induction P(n) is true.

shaalaa.com
Mathematical Induction
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Combinatorics and Mathematical Induction - Exercise 4.4 [पृष्ठ १९६]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 4 Combinatorics and Mathematical Induction
Exercise 4.4 | Q 5 | पृष्ठ १९६

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