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प्रश्न
Value of (256)0.16 × (256)0.09 is ______.
विकल्प
4
16
64
256.25
उत्तर
Value of (256)0.16 × (256)0.09 is 4.
Explanation:
Given: Number (256)0.16 × (256)0.09
= `(256)^(0.16 + 0.09)`
= (256)0.25
= `((2)^8)^1/4`
= (2)2
= 4
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संबंधित प्रश्न
Rationalise the denominator of each of the following
`1/sqrt12`
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`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(sqrt5 + 1)/sqrt2`
Express the following with rational denominator:
`1/(3 + sqrt2)`
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`(3 - sqrt5)/(3 + 2sqrt5)`
Simplify: \[\frac{3\sqrt{2} - 2\sqrt{3}}{3\sqrt{2} + 2\sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}\]
If x= \[\sqrt{2} - 1\], then write the value of \[\frac{1}{x} . \]
Rationalise the denominator of the following:
`1/(sqrt7-sqrt6)`
Simplify the following:
`3/sqrt(8) + 1/sqrt(2)`
Rationalise the denominator of the following:
`16/(sqrt(41) - 5)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`1/(sqrt(3) + sqrt(2))`
