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Chapters
2: Polynomials
3: Coordinate Geometry
4: Linear Equation In Two Variables
5: Introduction To Euclid's Geometry
6: Lines & Angles
7: Triangles
8: Quadrilaterals
9: Areas of Parallelograms & Triangles
10: Circles
11: Construction
12: Heron's Formula
13: Surface Area & Volumes
14: Statistics & Probability
![NCERT Exemplar solutions for Mathematics [English] Class 9 chapter 1 - Number Systems NCERT Exemplar solutions for Mathematics [English] Class 9 chapter 1 - Number Systems - Shaalaa.com](/images/mathematics-english-class-9_6:5f2b1b2038084cf381bfa42c826a928c.jpg)
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Solutions for Chapter 1: Number Systems
Below listed, you can find solutions for Chapter 1 of CBSE NCERT Exemplar for Mathematics [English] Class 9.
NCERT Exemplar solutions for Mathematics [English] Class 9 1 Number Systems Exercise 1.1 [Pages 2 - 5]
Choose the correct alternative:
Every rational number is ______.
a natural number
an integer
a real number
a whole number
Between two rational numbers ______.
there is no rational number
there is exactly one rational number
there are infinitely many rational numbers
there are only rational numbers and no irrational numbers
Decimal representation of a rational number cannot be ______.
terminating
non-terminating
non-terminating repeating
non-terminating non-repeating
The product of any two irrational numbers is ______.
always an irrational number
always a rational number
always an integer
sometimes rational, sometimes irrational
The decimal expansion of the number `sqrt(2)` is ______.
a finite decimal
1.41421
non-terminating recurring
non-terminating non-recurring
Which of the following is irrational?
`sqrt(4/9)`
`sqrt(12)/sqrt(3)`
`sqrt(7)`
`sqrt(81)`
Which of the following is irrational?
0.14
`0.14bar16`
`0.bar1416`
0.4014001400014...
A rational number between `sqrt(2)` and `sqrt(3)` is ______.
`(sqrt(2) + sqrt(3))/2`
`(sqrt(2) * sqrt(3))/2`
1.5
1.8
The value of 1.999... in the form `p/q`, where p and q are integers and q ≠ 0, is ______.
`19/10`
`1999/1000`
2
`1/9`
`2sqrt(3) + sqrt(3)` is equal to ______.
`2sqrt(6)`
6
`3sqrt(3)`
`4sqrt(6)`
`sqrt(10) xx sqrt(15)` is equal to ______.
`6sqrt(5)`
`5sqrt(6)`
`sqrt(25)`
`10sqrt(5)`
The number obtained on rationalising the denominator of `1/(sqrt(7) - 2)` is ______.
`(sqrt(7) + 2)/3`
`(sqrt(7) - 2)/3`
`(sqrt(7) + 2)/5`
`(sqrt(7) + 2)/45`
`1/(sqrt(9) - sqrt(8))` is equal to ______.
`1/2(3 - 2sqrt(2))`
`1/(3 + 2sqrt(2)`
`3 - 2sqrt(2)`
`3 + 2sqrt(2)`
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
13
19
5
35
The value of `(sqrt(32) + sqrt(48))/(sqrt(8) + sqrt(12))` is equal to ______.
`sqrt(2)`
2
4
8
If `sqrt(2) = 1.4142`, then `sqrt((sqrt(2) - 1)/(sqrt(2) + 1))` is equal to ______.
2.4142
5.8282
0.4142
0.1718
`root(4)root(3)(2^2)` equals to ______.
`2^(-1/6)`
`2^-6`
`2^(1/6)`
`2^6`
The product `root(3)(2) * root(4)(2) * root(12)(32)` equals to ______.
`sqrt(2)`
2
`root(12)(2)`
`root(12)(32)`
Value of `root(4)((81)^-2)` is ______.
`1/9`
`1/3`
9
`1/81`
Value of (256)0.16 × (256)0.09 is ______.
4
16
64
256.25
Which of the following is equal to x?
`x^(12/7) - x^(5/7)`
`root(12)((x^4)^(1/3)`
`(sqrt(x^3))^(2/3)`
`x^(12/7) xx x^(7/12)`
NCERT Exemplar solutions for Mathematics [English] Class 9 1 Number Systems Exercise 1.2 [Pages 6 - 7]
Let x and y be rational and irrational numbers, respectively. Is x + y necessarily an irrational number? Give an example in support of your answer.
Let x be rational and y be irrational. Is xy necessarily irrational? Justify your answer by an example.
State whether the following statement is True or False:
`sqrt(2)/3` is a rational number.
True
False
There are infinitely many integers between any two integers.
True
False
Number of rational numbers between 15 and 18 is finite.
True
False
There are numbers which cannot be written in the form `p/q, q ≠ 0, p, q` both are integers.
True
False
The square of an irrational number is always rational.
True
False
`sqrt(12)/sqrt(3)` is not a rational number as `sqrt(12)` and `sqrt(3)` are not integers.
True
False
`sqrt(15)/sqrt(3)` is written in the form `p/q, q ≠ 0` and so it is a rational number.
True
False
Classify the following number as rational or irrational with justification:
`sqrt(196)`
Classify the following number as rational or irrational with justification:
`3sqrt(18)`
Classify the following number as rational or irrational with justification:
`sqrt(9/27)`
Classify the following number as rational or irrational with justification:
`sqrt(28)/sqrt(343)`
Classify the following number as rational or irrational with justification:
`- sqrt(0.4)`
Classify the following number as rational or irrational with justification:
`sqrt(12)/sqrt(75)`
Classify the following number as rational or irrational with justification:
0.5918
Classify the following number as rational or irrational with justification:
`(1 + sqrt(5)) - (4 + sqrt(5))`
Classify the following number as rational or irrational with justification:
10.124124...
Classify the following number as rational or irrational with justification:
1.010010001...
NCERT Exemplar solutions for Mathematics [English] Class 9 1 Number Systems Exercise 1.3 [Pages 9 - 11]
Find whether the variable x represents a rational or an irrational number:
x2 = 5
Find whether the variable y represents a rational or an irrational number:
y2 = 9
Find whether the variable z represents a rational or an irrational number:
z2 = 0.04
Find whether the variable u represents a rational or an irrational number:
`u^2 = 17/4`
Find three rational numbers between –1 and –2
Find three rational numbers between 0.1 and 0.11
Find three rational numbers between `5/7` and `6/7`
Find three rational numbers between `1/4` and `1/5`
Insert a rational number and an irrational number between the following:
2 and 3
Insert a rational number and an irrational number between the following:
0 and 0.1
Insert a rational number and an irrational number between the following:
`1/3` and `1/2`
Insert a rational number and an irrational number between the following:
`(-2)/5` and `1/2`
Insert a rational number and an irrational number between the following:
0.15 and 0.16
Insert a rational number and an irrational number between the following:
`sqrt(2)` and `sqrt(3)`
Insert a rational number and an irrational number between the following:
2.357 and 3.121
Insert a rational number and an irrational number between the following:
0.0001 and 0.001
Insert a rational number and an irrational number between the following:
3.623623 and 0.484848
Insert a rational number and an irrational number between the following:
6.375289 and 6.375738
Represent the following number on the number line:
7
Represent the following number on the number line:
7.2
Represent the following number on the number line:
`(-3)/2`
Represent the following number on the number line:
`(-12)/5`
Locate `sqrt(5), sqrt(10)` and `sqrt(17)` on the number line.
Represent geometrically the following number on the number line:
`sqrt(4.5)`
Represent geometrically the following number on the number line:
`sqrt(5.6)`
Represent geometrically the following number on the number line:
`sqrt(8.1)`
Represent geometrically the following number on the number line:
`sqrt(2.3)`
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.2
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.888...
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
`5.bar2`
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
`0.bar001`
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.2555...
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
`0.1bar34`
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.00323232...
Express the following in the form `p/q`, where p and q are integers and q ≠ 0:
0.404040...
Show that 0.142857142857... = `1/7`
Simplify the following:
`sqrt(45) - 3sqrt(20) + 4sqrt(5)`
Simplify the following:
`sqrt(24)/8 + sqrt(54)/9`
Simplify the following:
`4sqrt12 xx 7sqrt6`
Simplify the following:
`4sqrt(28) ÷ 3sqrt(7) ÷ root(3)(7)`
Simplify the following:
`3sqrt(3) + 2sqrt(27) + 7/sqrt(3)`
Simplify the following:
`(sqrt(3) - sqrt(2))^2`
Simplify the following:
`root(4)(81) - 8root(3)(216) + 15root(5)(32) + sqrt(225)`
Simplify the following:
`3/sqrt(8) + 1/sqrt(2)`
Simplify the following:
`(2sqrt(3))/3 - sqrt(3)/6`
Rationalise the denominator of the following:
`2/(3sqrt(3)`
Rationalise the denominator of the following:
`sqrt(40)/sqrt(3)`
Rationalise the denominator of the following:
`(3 + sqrt(2))/(4sqrt(2))`
Rationalise the denominator of the following:
`16/(sqrt(41) - 5)`
Rationalise the denominator of the following:
`(2 + sqrt(3))/(2 - sqrt(3))`
Rationalise the denominator of the following:
`sqrt(6)/(sqrt(2) + sqrt(3))`
Rationalise the denominator of the following:
`(sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))`
Rationalise the denominator of the following:
`(3sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3))`
Rationalise the denominator of the following:
`(4sqrt(3) + 5sqrt(2))/(sqrt(48) + sqrt(18))`
Find the value of a and b in the following:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`
Find the value of a and b in the following:
`(3 - sqrt(5))/(3 + 2sqrt(5)) = asqrt(5) - 19/11`
Find the value of a and b in the following:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = 2 - bsqrt(6)`
Find the value of a and b in the following:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`
If `a = 2 + sqrt(3)`, then find the value of `a - 1/a`.
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`4/sqrt(3)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`6/sqrt(6)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`sqrt(2)/(2 + sqrt(2)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`1/(sqrt(3) + sqrt(2))`
Simplify:
`(1^3 + 2^3 + 3^3)^(1/2)`
Simplify:
`(3/5)^4 (8/5)^-12 (32/5)^6`
Simplify:
`(1/27)^((-2)/3)`
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
Simplify:
`(9^(1/3) xx 27^(-1/2))/(3^(1/6) xx 3^(- 2/3))`
Simplify:
`64^(-1/3)[64^(1/3) - 64^(2/3)]`
Simplify:
`(8^(1/3) xx 16^(1/3))/(32^(-1/3))`
NCERT Exemplar solutions for Mathematics [English] Class 9 1 Number Systems Exercise 1.4 [Page 12]
Express `0.6 + 0.bar7 + 0.4bar7` in the form `p/q`, where p and q are integers and q ≠ 0.
Simplify:
`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2))`
If `sqrt(2) = 1.414, sqrt(3) = 1.732`, then find the value of `4/(3sqrt(3) - 2sqrt(2)) + 3/(3sqrt(3) + 2sqrt(2))`.
If `a = (3 + sqrt(5))/2`, then find the value of `a^2 + 1/a^2`.
If `x = (sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))` and `y = (sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2))`, then find the value of x2 + y2.
Simplify:
`(256)^(-(4^((-3)/2))`
Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`
Solutions for 1: Number Systems
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NCERT Exemplar solutions for Mathematics [English] Class 9 chapter 1 - Number Systems
Shaalaa.com has the CBSE Mathematics Mathematics [English] Class 9 CBSE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT Exemplar solutions for Mathematics Mathematics [English] Class 9 CBSE 1 (Number Systems) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. NCERT Exemplar textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in Mathematics [English] Class 9 chapter 1 Number Systems are Introduction of Real Number, Concept of Irrational Numbers, Real Numbers and Their Decimal Expansions, Representing Real Numbers on the Number Line, Operations on Real Numbers, Laws of Exponents for Real Numbers.
Using NCERT Exemplar Mathematics [English] Class 9 solutions Number Systems exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in NCERT Exemplar Solutions are essential questions that can be asked in the final exam. Maximum CBSE Mathematics [English] Class 9 students prefer NCERT Exemplar Textbook Solutions to score more in exams.
Get the free view of Chapter 1, Number Systems Mathematics [English] Class 9 additional questions for Mathematics Mathematics [English] Class 9 CBSE, and you can use Shaalaa.com to keep it handy for your exam preparation.