Advertisements
Advertisements
प्रश्न
Simplify:
`[((625)^(-1/2))^((-1)/4)]^2`
उत्तर
`[((625)^(-1/2))^((-1)/4)]^2 = [((25^2)^(-1/2))^(-1/4)]^2` ...[∵ (am)n = amn]
= `(25^-1)^(-1/4 xx 2)`
= `[(5^2)^-1]^(-1/4 xx 2)`
= `5^(-2 xx -1/4 xx 2)`
= 51
= 5
APPEARS IN
संबंधित प्रश्न
Simplify the following expressions:
`(3 + sqrt3)(5 - sqrt2)`
Simplify the following expressions:
`(sqrt5 - 2)(sqrt3 - sqrt5)`
Simplify the following expression:
`(sqrt5 - sqrt2)(sqrt5 + sqrt2)`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`3/sqrt10`
Find the value to three places of decimals of the following. It is given that
`sqrt2 = 1.414`, `sqrt3 = 1.732`, `sqrt5 = 2.236` and `sqrt10 = 3.162`
`(2 + sqrt3)/3`
Simplify `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + sqrt12/(sqrt3 - sqrt2)`
Classify the following number as rational or irrational:
`(3+sqrt23)-sqrt23`
Simplify the following:
`(sqrt(3) - sqrt(2))^2`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`4/sqrt(3)`
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`(sqrt(10) - sqrt(5))/2`
