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If 2=1.414,3=1.732, then find the value of 433-22+333+22. - Mathematics

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प्रश्न

If `sqrt(2) = 1.414, sqrt(3) = 1.732`, then find the value of `4/(3sqrt(3) - 2sqrt(2)) + 3/(3sqrt(3) + 2sqrt(2))`.

योग

उत्तर

We have, `4/(3sqrt(3) - 2sqrt(2)) + 3/(3sqrt(3) + 2sqrt(2))`

= `(4(3sqrt(3) + 2sqrt(2)) + 3(3sqrt(3) - 2sqrt(2)))/((3sqrt(3) - 2sqrt(2))(3sqrt(3) + 2sqrt(2))`

= `(12sqrt(3) + 8sqrt(2) + 9sqrt(3) - 6sqrt(2))/((3sqrt(3))^2 - (2sqrt(2))^2`  ...[Using identity, (a + b)(a – b) = a2 – b2]

= `(21sqrt(3) + 2sqrt(2))/(27 - 8)`

= `(21sqrt(3) + 2sqrt(2))/19`

= `(21 xx 1.732 + 2 xx 1.414)/19`  ...`["Put"  sqrt(2) = 1.414  "and"  sqrt(3) = 1.732]`

= `(36.372 + 2.828)/19`

= `39.2/19`

= 2.06316

= 2.063

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अध्याय 1: Number Systems - Exercise 1.4 [पृष्ठ १२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 9
अध्याय 1 Number Systems
Exercise 1.4 | Q 3. | पृष्ठ १२

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