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प्रश्न
Write the length (magnitude) of a vector whose projections on the coordinate axes are 12, 3 and 4 units.
उत्तर
Given: Projection on the coordinate axes are 12, 3, 4 units.
Therefore, Length of vector
\[= \sqrt{{12}^2 + 3^2 + 4^2}\]
= \[\sqrt{169}\]
= 13
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