Advertisements
Advertisements
प्रश्न
A(1, 4), B(3, 2) and C(7, 5) are vertices of a triangle ABC. Find the equation of a line, through the centroid and parallel to AB.
उत्तर
Slope of the line parallel to AB = Slope of AB = −1
Thus, the required equation of the line is
y – y1 = m(x – x1)
`y - 11/3 = -1(x - 11/3)`
`y - 11/3 = -x + 11/3`
`y + x = 11/3 + 11/3`
`y + x = (11 + 11)/3`
= `22/3`
3y + 3x = 22
APPEARS IN
संबंधित प्रश्न
The equation of a line 3x + 4y − 7 = 0. Find
1) The slope of the line.
2) The equation of a line perpendicular to the given line and passing through the intersection of the lines x – y + 2 = 0 and 3x + y – 10 = 0.
The co-ordinates of two points A and B are (-3, 4) and (2, -1) Find: the co-ordinates of the point where the line AB intersects the y-axis.
Determine whether the line through points (–2, 3) and (4, 1) is perpendicular to the line 3x = y + 1.
Does line 3x = y + 1 bisect the line segment joining the two given points?
The vertices of a ΔABC are A(3, 8), B(–1, 2) and C(6, –6). Find:
(i) Slope of BC
(ii) Equation of a line perpendicular to BC and passing through A.
Find the value of a line parallel to the following line:
`(2"x")/5 + "y"/3` = 2
ABCD is rhombus. The coordinates of A and C ae (3,7) and (9,15). Find the equation of BD.
Find the value of a for which the points A(a, 3), B(2, 1) and C(5, a) are collinear. Hence, find the equation of the line.
Find the equation of a line that has Y-intercept 3 units and is perpendicular to the line joining (2, – 3) and (4, 2).
Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0.
In the adjoining figure, write
(i) The coordinates of A, B and C.
(ii) The equation of the line through A and | | to BC.
