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A Bag Contains 25 Tickets, Numbered from 1 to 25. a Ticket is Drawn and Then Another Ticket is Drawn Without Replacement. Find the Probability that Both Tickets Will Show Even Numbers. - Mathematics

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प्रश्न

A bag contains 25 tickets, numbered from 1 to 25. A ticket is drawn and then another ticket is drawn without replacement. Find the probability that both tickets will show even numbers.

उत्तर

There are 12 even numbers between 1 to 25.

Consider the given events.
A = An even number ticket in the first draw
B = An even number ticket in the second draw

\[\text{ Now } , \]
\[P\left( A \right) = \frac{12}{25}\]
\[P\left( B/A \right) = \frac{11}{24}\]
\[ \therefore \text{ Required probability } = P\left( A \cap B \right) = P\left( A \right) \times P\left( B/A \right) = \frac{12}{25} \times \frac{11}{24} = \frac{11}{50}\]

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Probability Examples and Solutions
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पाठ 31: Probability - Exercise 31.2 [पृष्ठ २२]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 31 Probability
Exercise 31.2 | Q 4 | पृष्ठ २२

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