मराठी

A Bag Contains 3 White and 2 Black Balls and Another Bag Contains 2 White and 4 Black Balls. One Bag is Chosen at Random. from the Selected Bag, One Ball is Drawn. - Mathematics

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प्रश्न

A bag contains 3 white and 2 black balls and another bag contains 2 white and 4 black balls. One bag is chosen at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is white.

उत्तर

A white ball can be drawn in two mutually exclusive ways:
(I) Selecting bag I and then drawing a white ball from it
(II) Selecting bag II and then drawing a white ball from it
Let E1E2 and A be the events as defined below:
E1 = Selecting bag I
E2 = Selecting bag II
A = Drawing a white ball
It is given that one of the bags is selected randomly.

\[\therefore P\left( E_1 \right) = \frac{1}{2} \]

\[ P\left( E_2 \right) = \frac{1}{2}\]

\[ \text{ Now } , \]

\[P\left( A/ E_1 \right) = \frac{3}{5}\]

\[P\left( A/ E_2 \right) = \frac{2}{6} = \frac{1}{3}\]

\[\text{ Using the law of total probability, we get } \]

\[\text{ Required probability}  = P\left( A \right) = P\left( E_1 \right)P\left( A/ E_1 \right) + P\left( E_2 \right)P\left( A/ E_2 \right)\]

\[ = \frac{1}{2} \times \frac{3}{5} + \frac{1}{2} \times \frac{1}{3}\]

\[ = \frac{3}{10} + \frac{1}{6}\]

\[ = \frac{9 + 5}{30} = \frac{14}{30} = \frac{7}{15}\]

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Probability Examples and Solutions
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पाठ 31: Probability - Exercise 31.6 [पृष्ठ ८१]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 31 Probability
Exercise 31.6 | Q 4 | पृष्ठ ८१

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