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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

A person wants to create a fund of ₹6,96,150 after 4 years at the time of his retirement. He decides to invest a fixed amount at the end of every year in a bank that offers him interest of 10% p.a. - Mathematics and Statistics

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प्रश्न

A person wants to create a fund of ₹6,96,150 after 4 years at the time of his retirement. He decides to invest a fixed amount at the end of every year in a bank that offers him interest of 10% p.a. compounded annually. What amount should he invest every year? [Given (1.1)4 = 1.4641]

बेरीज

उत्तर

Given, A = ₹6,96,150, n = 4 years, r = 10% p.a. 

i = `"r"/(100) = (10)/(100)` = 0.1

Now, A = `"C"/"i" [(1 + "i")^"n" - 1]`

∴ 6,96,150 = `"C"/(0.1)[(1 + 0.1)^4 - 1]`

∴ 6,96,150 x 0.1= C[(1.1)4 – 1]

∴ 69,615 = C[1.4641 – 1]
∴ 69,615 = C(0.4641)

∴ C = `(69, 615)/(0.4641)`
∴ C = 1,50,000
∴ Sum of ₹1,50,000 should be invested every year.

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Annuity
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Insurance and Annuity - Exercise 2.2 [पृष्ठ २८]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] 12 Standard HSC Maharashtra State Board
पाठ 2 Insurance and Annuity
Exercise 2.2 | Q 1.08 | पृष्ठ २८

संबंधित प्रश्‍न

A person invested ₹ 5,000 every year in finance company that offered him interest compounded at 10% p.a., what is the amount accumulated after 4 years? [Given (1.1)4 = 1.4641]


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Find the rate of interest compounded annually if an annuity immediate at ₹20,000 per year amounts to ₹2,60,000 in 3 years.


Find the accumulated value of annuity due of ₹1,000 p.a. for 3 years at 10% p.a. compounded annually. [Given (1.1)3 = 1.331]


A person plans to put ₹400 at the beginning of each year for 2 years in a deposit that gives interest at 2% p.a. compounded annually. Find the amount that will be accumulated at the end of 2 years.


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Choose the correct alternative :

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The person who receives annuity is called __________.


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The intervening time between payment of two successive installments is called as ___________.


Solve the following :

Find the least number of years for which an annuity of ₹3,000 per annum must run in order that its amount exceeds ₹60,000 at 10% compounded annually. [(1.1)11 = 2.8531, (1.1)12 = 3.1384]


Solve the following :

After how many years would an annuity due of ₹3,000 p.a. accumulated ₹19,324.80 at 20% p. a. compounded yearly? [Given (1.2)4 = 2.0736]


Multiple choice questions:

Rental payment for an apartment is an example of ______


Multiple choice questions:

In an ordinary annuity, payments or receipts occur at ______


State whether the following statement is True or False:

A sinking fund is a fund established by financial organization


State whether the following statement is True or False:

The relation between accumulated value ‘A’ and present value ‘P’ is A = P(1+ i)n 


An annuity in which each payment is made at the end of period is called ______


The intervening time between payment of two successive installments is called as ______


For annuity due,

C = ₹ 20,000, n = 3, I = 0.1, (1.1)–3 = 0.7513

Therefore, P = `square/0.1 xx [1 - (1 + 0.1)^square]`

= 2,00,000 [1 – 0.7513]

= ₹ `square`


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