Advertisements
Advertisements
प्रश्न
ABCD is a rectangle with ∠ABD = 40°. Determine ∠DBC .
उत्तर
We have,
`∠`ABC = 90°
⇒ `∠`ABD + `∠`DBC = 90° [ ∵ `∠`ABD = 40°]
⇒ 40° + `∠`DBC = 90°
∴`∠`DBC = 50°
APPEARS IN
संबंधित प्रश्न
Diagonal AC of a parallelogram ABCD bisects ∠A (see the given figure). Show that
- It bisects ∠C also,
- ABCD is a rhombus
State, 'true' or 'false'
The diagonals of a parallelogram bisect each other at right angle.
State, 'true' or 'false'
Every rhombus is a parallelogram.
State, 'true' or 'false'
Every parallelogram is a rhombus.
In the given figure ABCD is a rhombus with angle A = 67°
If DEC is an equilateral triangle, calculate:
- ∠CBE
- ∠DBE
In the given figure, PQRS is a ∥ gm. A straight line through P cuts SR at point T and QR produced at N. Prove that area of triangle QTR is equal to the area of triangle STN.
In the given figure, PT ∥ QR and QT ∥ RS. Show that: area of ΔPQR = area of ΔTQS.
*Question modified
One side of a parallelogram is 12cm and the altitude corresponding to i is 8cm. If the length of the altitude corresponding to its adjacent side is 16cm, find the length of the adjacent side.
The area of a floor of a rectangular room is 360m2. If its length is 24cm, find its perimeter.
The opposite sides of a trapezium are parallel.
