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Answer briefly. State the expression for apparent frequency when source of sound and listener are moving towards each other moving away from each other - Physics

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प्रश्न

Answer briefly.

State the expression for apparent frequency when source of sound and listener are

  1. moving towards each other
  2. moving away from each other
टीपा लिहा

उत्तर

  1. Let, n0 = actual frequency of the source.
    n = apparent frequency of the source.
    v = velocity of sound in air.
    vs = velocity of the source.
    vL = velocity of the listener.
  2. Apparent frequency heard by the listener is given by, n =`"n"_0 (("v" +- "v"_"L")/("v" bar+ "v"_"s"))`
    Where upper signs (+ ve in numerator and -ve in denominator) indicate that the source and observer move towards each other. Lower signs (-ve in numerator and +ve in denominator) indicate that the source and listener move away from each other.
  3. If source and listener are moving towards each other, then apparent frequency is given by,
    n = `"n"_0(("v" + "v"_"L")/("v" - "v"_"s"))` i.e., apparent frequency increases.
  4. If source and listener are moving away from each other, then apparent frequency is given by, 
    n = `"n"_0(("v" - "v"_"L")/("v" + "v"_"s"))` i.e., apparent frequency decreases.
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Doppler Effect
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पाठ 8: Sound - Exercises [पृष्ठ १५८]

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बालभारती Physics [English] 11 Standard Maharashtra State Board
पाठ 8 Sound
Exercises | Q 2. (xiv) | पृष्ठ १५८

संबंधित प्रश्‍न

A narrow sound pulse (for example, a short pip by a whistle) is sent across a medium. (a) Does the pulse have a definite (i) frequency, (ii) wavelength, (iii) speed of propagation? (b) If the pulse rate is 1 after every 20 s, (that is the whistle is blown for a split of second after every 20 s), is the frequency of the note produced by the whistle equal to 1/20 or 0.05 Hz


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