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Answer in brief: Explain what is optical path length. How is it different from actual path length? - Physics

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Answer in brief:

Explain what is the optical path length. How is it different from actual path length?

What is Optical Path length? How is it different from the actual Path length? 

थोडक्यात उत्तर

उत्तर १

Consider, a light wave with an angular frequency of w and a wave vector of k travelling in the x-direction through a vacuum. The phase of this wave is (kx - ωt). In a vacuum, light speed at c, but in a medium, it speeds at v.

k = `(2pi)/lambda = (2pi v)/(v lambda) = omega/v` as ω = 2πv and v = vλ, where v is the frequency of light.

If the wave travels a distance Δ x, its phase changes by Δ Φ = kΔx = ω Δx/v.

Similarly, if the wave is travelling in vacuum,

k = ω/c and Δ Φ = ω Δ x/c

Now, consider a wave travelling a distance Δ x in the medium, the phase difference generated is,

Δ Φ' = k' Δ x = ωn Δ x/c = ω Δ x'/c     ...(1)

where Δ x' = n Δ x              .....(2)

The distance nΔ x is called the optical path length of the light in the medium; it is the distance the light would have travelled in the same time t in vacuum (with the speed c).

The optical path length in a medium is the corresponding path in a vacuum that light traverses at the same time as it does in the medium.

Now, speed = `"distance"/"time"`

∴ time = `"distance"/"speed"`

∴ t = `"d"_"medium"/"v"_"medium" = "d"_"vaccum"/"v"_"vaccum"`

Hence, the optical path = `"d"_"vacuum"`

`= "v"_"vaccum"/"v"_"medium" xx "d"_"medium"`

`= "n" xx "d"_"medium"`

Thus, a distance d travelled in a medium of refractive index n introduces a path difference = nd - d = d (n - 1) over a ray travelling equal distance through vacuum.

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उत्तर २

i. When a wave travels a distance Δx through a medium having a refractive index of n, its phase changes by the same amount as it would if the wave had travelled a distance nΔx in a vacuum. 

ii. Thus, a path length of Δx in a medium of refractive index n is equivalent to a path length of nΔx in a vacuum.

iii. nΔx is called the optical path travelled by a wave.

iv. This means, the optical path through a medium is the effective path travelled by light in a vacuum to generate the same phase difference.

v. Optical path in a medium can also be defined as the corresponding path in a vacuum that the light travels at the same time as it takes in the given medium.

i.e., time = `"d"_"medium"/"v"_"medium" = "d"_"vacuum"/"v"_"vacuum"`

∴ `"d"_"vacuum" = "v"_"vacuum"/"v"_"medium" xx "d"_"medium" = "n" xx "d"_"medium"`

But `"d"_"vacuum"` = Optical path  

∴ Optical path = n × `"d"_"medium"`

Thus, a distance d travelled in a medium of refractive index n introduces a path difference = nd - d = d(n - 1) over a ray travelling an equal distance through the vacuum.  

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पाठ 7: Wave Optics - Exercises [पृष्ठ १८४]

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बालभारती Physics [English] 12 Standard HSC Maharashtra State Board
पाठ 7 Wave Optics
Exercises | Q 2.5 | पृष्ठ १८४

संबंधित प्रश्‍न

Laser light of wavelength 630 nm is incident on a pair of slits which are separated by 1.8 mm. If the screen is kept 80 cm away from the two slits, calculate:

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Answer the following question.
Describe any two characteristic features which distinguish between interference and diffraction phenomena. Derive the expression for the intensity at a point of the interference pattern in Young's double-slit experiment.


Answer in brief:

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